The sum of the squares of three consecutive odd numbers is 2531. What is the smallest number?
(A) 13 (B) 27 (C)23 (D).33
Answer: B
Description:
Let the numbers be x, x + 2 and x + 4.
Then, X2 + (x + 2)2 + (x + 4)2 = 2531 => 3x2 + 12x - 2511 = 0
X2 + 4x - 837 = 0 => (x - 27) (x + 31) = 0 => x = 27.
Hence, the numbers are 27, 29 and 31.
So , Smallest number is 27
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